VALTREX FOR SALE, A large unpressurized tank containing gasoline is hit by a high velocity rock that is kicked up by a lawn mower. The rock creates a 0.5 in hole in the tank 2 ft below the surface of the gasoline (SG=0.8). Just before the rock hits the tank, VALTREX mg, what is the hydrostatic pressure (psig) at the place where the rock will strike. Buy VALTREX online no prescription,
Answer
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First off, let's assume that this scenario is taking place on Earth, buy VALTREX without a prescription, near sea level, Online buying VALTREX hcl, and that neither the tank in question nor its contents are not in motion.
Short Answer
Using SI units, the equation for hydrostatic pressure is P = d*g*h, after VALTREX, where P is the hydrostatic pressure, Where can i find VALTREX online, d is density, g is the acceleration due to gravity, and h is the vertical height (or head) of liquid above the point being considered, purchase VALTREX online. The density of the gasoline is d = 0.8*d_water, VALTREX treatment, so d = 0.8*1000 kg/m^3, or 800 kg/m^3. The acceleration due to gravity is 9.81 m/s^2, buy VALTREX from canada, and h is 2 ft, VALTREX from canadian pharmacy, or 0.61 m. VALTREX FOR SALE, This leads to an answer of P = (800 kg/m^3)*(9.81 m/s^2)*(0.61m) = 4787 N/m^2, or 4787 Pa. Since 6895 Pa = 1 psig, the final answer would be 4787 Pa / (6895 Pa/psig) = 0.694 psig, VALTREX maximum dosage.
Longer Answer
Using AES units, VALTREX photos, the equation for hydrostatic pressure is P = d*g/g_c*h, where P is the hydrostatic pressure, d is density, VALTREX blogs, g is the acceleration due to gravity, Buy cheap VALTREX, g_c is the conversion factor necessary for converting between lb_m and lb_f, and h is the vertical height (or head) of liquid above the point being considered. The density of the gasoline is d = 0.8*d_water, herbal VALTREX, so d = 0.8*62.4 lb_m/ft^3, Discount VALTREX, or 49.9 lb_m/ft^3. The acceleration due to gravity is 32.2 ft/s^2, and g_c is equal to 32.174 ft*lb_m/(s^2*lb_f), VALTREX images. Lastly, h = 2 ft, and remembering that there are 144 in^2 in 1 ft^2, we can finally calculate the answer: P = (49.9 lb_m/ft^3)*(32.2 ft/s^2)/(32.174 ft*lb_m/(s^2*lb_f))*(2ft)*(1 ft^2 / 144 in^2) = 0.694 psig, VALTREX FOR SALE.
Longest Answer
Since the rock creates a 0.5 in (diameter) hole, Buy cheap VALTREX no rx, and the question asks what the hydrostatic pressure is at "the place where the rock will strike," we can choose not to treat the area in question as a point. Thus, VALTREX reviews, there will be a small pressure differential between the top and the bottom of where the rock strikes. VALTREX brand name, Using the previously derived answer of 0.694 psig at the point exactly 2 ft below the top of the tank, we can treat this point as the center of a disk of 0.25 in radius. Since hydrostatic pressure scales linearly with depth (in other words, online buying VALTREX, d and g in P = d*g*h are constant), Doses VALTREX work, we can do a simple scaling to determine the pressure at the top of the hole. VALTREX FOR SALE, This yields 0.694 psig/24 inches * 23.75 inches = 0.687 psig at the top of the hole. For the bottom, we can use the same strategy: 0.694 psig/24 inches * 24.25 inches = 0.701 psig, where can i buy VALTREX online. Thus, we can create an equation that describes the hydrostatic pressure at any depth between 23.75 inches and 24.25 inches: (0.694 psig)*(1 + x/(24 inches)), where x can vary in the range [-0.25 in, 0.25 in], where the top of the tank is 0 inches in depth. This yields, as shown above, a range between 0.687 psig and 0.701 psig. Using Bernoulli's equation, we can see that this is pretty small, only enough to make the fluid velocity difference between the top and bottom of the hole when the leak is sprung about 0.1 ft/s.
Image: Lawnmower, gary turner
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hydrostatic pressure 31.36 pascal
That is incorrect. The pressure should be only slightly higher than atmospheric conceptually as we are assuming that the tank is at atmospheric pressure since it is an unpressurized tank.